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Sandy is flying a Cessna and is descending at a 6° angle towards a landing field. If she can see a gorge behind her at a 65° angle that is 400 meters away from thelanding field, how much further does she have to fly until she lands? Round to the nearest tenth.e

Sandy is flying a Cessna and is descending at a 6 angle towards a landing field If she can see a gorge behind her at a 65 angle that is 400 meters away from the class=

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Solution:

Given:

From the sketch of the flight description, using the sine rule,

[tex]\begin{gathered} \frac{400}{\sin109}=\frac{y}{\sin 65} \\ y=\frac{400\times\sin 65}{\sin 109} \\ y\approx383.4m \end{gathered}[/tex]

Therefore, she has to fly approximately 383.4m further until she lands.

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