First, take two points, and find the slope.
[tex]\text{Slope } = \frac{ y_2 - y_1 } { x_2 - x_1 } = \frac{ 11 - 2}{ 8 - 2} = \frac{ 9}{ 6} = \boxed{\bf{ \frac{3}{2}}}[/tex]
So now we have an equation:
y = 3/2x + b
Plug in the point (2,2) and solve for b.
2 = (3/2)(2) + b
2 = 3 + b
b = -1
The final equation that represents the relationship is y = 3/2x - 1.
