suppose that $2500 is deposited in a savings account paying 5% interest, compounded continuously. What will be the average value of the count during the next 10 years

suppose that 2500 is deposited in a savings account paying 5 interest compounded continuously What will be the average value of the count during the next 10 yea class=

Respuesta :

E none of these

Explanation

The continuous compounding formula says

[tex]\begin{gathered} A=P*e^{rt} \\ where \\ A\text{ is the final amount} \\ Pis\text{ the initial amount} \\ r\text{ is the rate of interest} \\ t\text{ is the time} \end{gathered}[/tex]

so

Step 1

find the final amount:

a)Let

[tex]\begin{gathered} P=2500 \\ r=5\text{ \% = }\frac{5}{100}=0.05 \\ time=\text{ 10 years} \end{gathered}[/tex]

b) now, replace

[tex]\begin{gathered} A=Pe^{rt} \\ A=2500(e^{0.05*10}) \\ A=2,500(e^{0.5}) \end{gathered}[/tex]

so, the final amout would be:

[tex]A=2,500(e^{0.5})[/tex]

Step 2

know to know the average, divide by the numbers of years

so

[tex]\begin{gathered} average=\frac{P}{time} \\ Average=\frac{2500(e^{0.5})}{10} \\ Average=250(e^{0.5}) \end{gathered}[/tex]

so, the answer is

E none of these

I hope this helps you