the circle below has center S. Suppose that mQR= 106°. Find the following(a) m

We have to find the measure of the angle QSR and the angle QPR.
The angle QSR is a central angle. This means that
[tex]\begin{gathered} m\hat{QR}=m\measuredangle QSR \\ m\measuredangle QSR=106^{\circ} \end{gathered}[/tex]The angle QPR is an inscribed angle, thus:
[tex]\begin{gathered} m\measuredangle QPR=\frac{1}{2}m\hat{QR} \\ m\measuredangle QPR=\frac{1}{2}\cdot106^{\circ}=53^{\circ} \end{gathered}[/tex]This means that m∡QSR=106° and m∡QPR=53°.