The vector in its generic form is given by:
v = lvl * (cos (theta) i + sin (theta) j)
Where,
lvl: magnitude of the vector
theta: direction angle
We have the following vector:
v = 6cos137degrees i + 6sin137degrees j.
Rewriting:
v = 6 (cos137degrees i + sin137degrees j)
Thus,
lvl = 6
theta = 137 degrees
Answer:
The magnitude and direction angle for the vector are:
A.) 6,137 degrees
