Answer: B) [tex] (y-6)=-3(x+1)[/tex]
Step-by-step explanation:
The equation ( in point slope form) of a line passing from (a,b) and has slope (m) is given by :-
[tex](y-b)=m(x-a)[/tex]
Now, the equation ( in point slope form) of the line that passes through the point (-1,6) and has a slope of -3 will be:-
[tex](y-6)=-3(x-(-1))\\\\\Rightarrow\ (y-6)=-3(x+1)[/tex]