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[tex]LINEAR \: \: EQUATION \: \: IN \: \: TWO \\ \: \: VARIABLES \\ \\ \\

Given \: system \: of \: equations \: - \\ \\ n \: = \: 2p \: + \: 3 \: \: \: - - - eq.(1) \\ \\ n \: = \: 5 \: + \: p \: \: \: - - - eq.(2) \\ \\ \: \\ Comparing \: eq.(1) \: \: and \: \: eq.(2) \: \\ We \: get \: \: -\\ \\ 2p \: + \: 3 \: = \: 5 \: + \: p \\ \\ 2p \: - \: p \: = \: 5 \: - \: 3 \\ \\ p \: = \: 2 \: \\ \\ Putting \: in \: eq.(1) \: \\ We \: get \: \: , \: \: n = 7 \\ \\ Hence \: \: \: .\\ \\ || \: \: p \: = \: 2\: \: \: \: || \: \: n = \: 7 \: \: \: || \\ \\ \\ Therefore \: , \: Solution \: of \: the \: given \: system \\ of \: equations \: is \: \: \: ( \: 2 \: , \: 7 \: ) \: \: \: \: \: \: \: \: \: Ans.[/tex]

Answer:

[tex][2, 7][/tex]

Step-by-step explanation:

5 + p = 2p + 3

- 2p - 2p

______________

5 - p = 3

-3 - 3

________

2 - p = 0

-2 - 2

________

-p = -2

2 = p [Plug this back into both equations above to get the n-term of 7]; 7 = p

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