[tex]SURFACE \: \: AREA \: \: AND \: \: VOLUMES \\ \\ \\
Volume \: \: of \: \: cone \: \: = \: \: \frac{1}{3} \pi {r}^{2} h \\ \\ \\ We \: are \: given \: that \: \: - \: \: \: \\ \: \: \\ \: Radius \: = \: 9 \: \: in. \\ \\ \: Height \: = \: 12 \: \: in. \\ \\ \: \: \: \pi \: = \: 3.14 \\ \\ Volume \: \:of \: \: Cone \: \: = \: \: \frac{1}{3} \times 3.14 \times 9 \times 9 \times 12 \\ \\ \\ Volume \: \: of \: \: Cone \: \: = \: \: 1017.36 \: {in.}^{3} [/tex]
