you spin a spinner twice. find the probability of the event as a reduced fraction or precent. #1: spinning a 3 then a 4.

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x represents the total number of numbers on the spinner

1 1
_ • _
x x

The probability of the event spinning a 3 then a 4 is 1/n²

How to determine the probability?

Assume that the numbers on the spinner appear only once, and there are n sections in the spinner.

The probability of obtaining a 3 is:

P(3) = 1/n

The probability of obtaining a 4 is:

P(4) = 1/n

The required probability is calculated as:

P  = P(3) * P(4)

So, we have:

P = 1/n * 1/n

Evaluate

P = 1/n²

Hence, the probability of the event spinning a 3 then a 4 is 1/n²

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