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Given: KLMN is a parallelogram,

KA
− angle bisector of ∠K

LA
− angle bisector of ∠L
Prove: m∠KAL = 90°

Respuesta :

sum of two adjacent angles of parallelogram is 180

so angle K + angle L = 180

as AK bisects angle K and LA bisects angle L

so, angle AKL + angle ALK = 180 /2 = 90

in triangle AKL,

angle AKL + angle ALK+angle KAL = 180(sum of all angles in triangle = 180)

so, from above two equations,

angle KAL = 90


jamiechen79

Answer:

wuts the answer its not sum of angles theorem but its 180 º and either

Complementary angles, consecutive angles of parallelogram supplementary, or exterior angles theorem.

Step-by-step explanation:

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