when q = M* C *ΔT
we can get the mass using the given volume & density:
M = volume * density
= 1.3 L * 1g/ml * 1000mL1L
= 1300 g
and when the specific heat of water = 4.18J/g.°C
now, by substitution:
∴ q = 1300g * 4.18J/g.°C * (100-24)
= 412984 J or 412.984 KJ
