contestada

Molecular weight of PbCl2 = 278 g/mole Mass of beaker + PbCl2 = 62.19 g Mass of beaker = 57.77 g Mass of PbCl2 per 100 mL = g Moles PbCl2 per 100 mL = [Pb-2] based upon this investigation = M [Cl-] based upon this investigation = M

Respuesta :

kenmyna
PbCl2--->Pb2+  +  2Cl-

The  mass   of  PbCl2   is   =mass   of  the  beaker+Pbcl2  minus   mass  of  the  beaker
that  is  62.19-57.77g=  4.42grams

moles  of PbCl2=  4.42g/278g/m0l = 0.0159moles

concentration  of  (Pb2+)
since  mole  ratio  of  PbCl2  to  Pb2+  is   1:1  therefore  the  moles  of  Pb2+  is  also  0.0159moles
concentration  =0.0159/100 x1000=0.159M

concentration  of  CI-  is  two  time  that  of  Pb2+  from  the  equation  above  therefore  concentration   of  Cl-  =  0.159 x2  =0.318M

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