Respuesta :

We solve the equation, ( a + a + 1 )^2 = 112 + a^2 + ( a + 1 )^2;
Then, ( 2a + 1 )^2 = 112 + a^2 + a^2 + 2a +1;
4a^2 + 4a + 1 = 113 + 2a^2 + 2a;
Finally, 2a^2 + 2a - 112 = 0;
a^2 + a - 56 = 0; 
We use Quadratic Formula for this Quadratic Equation;
The solutions are a1 = 7 and a2 = -8;
But a is a natural number; so, a = 7;
The natural consecutive numbers are 7 and 8.

The two consecutive numbers are 7 and 8.

Consecutive numbers are numbers that follow each other. For example, 1,2,3,4 are consecutive numbers.

Let:

x = first number

(x + 1) = second number

From the question, this expression can be derived:

[(x) + (x + 1)] ²

This can be simplified to (2x +1)²

The second expression is : x² + (x +1)²

(2x +1)² -  [x² + (x +1)²] = 112

expanding the bracket gives:

(4x²  + 4x + 1) - [x² + (x² + 2x +1) = 112

4x²  + 4x + 1 - 2x² - 2x - 1 = 112

Add like terms

2x² + 2x = 112

Divide both sides by 2

x² + x = 56

x² + x - 56 = 0

Factorise the equation

The factors of -56x² that add up to x are : 8x and -7x

(x² - 7x) (8x - 56)  = 0

x(x - 7) 8(x -7) = 0

x = 7

or

x = -8

Since x cannot be a negative number, x is 7 and (x + 1) = 8

A similar question was solved here: https://brainly.com/question/14024870?referrer=searchResults