Respuesta :
We solve the equation, ( a + a + 1 )^2 = 112 + a^2 + ( a + 1 )^2;
Then, ( 2a + 1 )^2 = 112 + a^2 + a^2 + 2a +1;
4a^2 + 4a + 1 = 113 + 2a^2 + 2a;
Finally, 2a^2 + 2a - 112 = 0;
a^2 + a - 56 = 0;
We use Quadratic Formula for this Quadratic Equation;
The solutions are a1 = 7 and a2 = -8;
But a is a natural number; so, a = 7;
The natural consecutive numbers are 7 and 8.
Then, ( 2a + 1 )^2 = 112 + a^2 + a^2 + 2a +1;
4a^2 + 4a + 1 = 113 + 2a^2 + 2a;
Finally, 2a^2 + 2a - 112 = 0;
a^2 + a - 56 = 0;
We use Quadratic Formula for this Quadratic Equation;
The solutions are a1 = 7 and a2 = -8;
But a is a natural number; so, a = 7;
The natural consecutive numbers are 7 and 8.
The two consecutive numbers are 7 and 8.
Consecutive numbers are numbers that follow each other. For example, 1,2,3,4 are consecutive numbers.
Let:
x = first number
(x + 1) = second number
From the question, this expression can be derived:
[(x) + (x + 1)] ²
This can be simplified to (2x +1)²
The second expression is : x² + (x +1)²
(2x +1)² - [x² + (x +1)²] = 112
expanding the bracket gives:
(4x² + 4x + 1) - [x² + (x² + 2x +1) = 112
4x² + 4x + 1 - 2x² - 2x - 1 = 112
Add like terms
2x² + 2x = 112
Divide both sides by 2
x² + x = 56
x² + x - 56 = 0
Factorise the equation
The factors of -56x² that add up to x are : 8x and -7x
(x² - 7x) (8x - 56) = 0
x(x - 7) 8(x -7) = 0
x = 7
or
x = -8
Since x cannot be a negative number, x is 7 and (x + 1) = 8
A similar question was solved here: https://brainly.com/question/14024870?referrer=searchResults