Respuesta :
Let us first write down the given equation.
80 = 3y + 2y + 4 + 1
80 = 5y + 5
80 - 5 = 5y
75 = 5y
Just reversing both sides we get
5y = 75
Now dividing both sides by 5 we get
y = 15
So the value of y is 15. I hope the procedure for solving the problem is clear to you. In future you can solve such problems with ease following the procedure described.
80 = 3y + 2y + 4 + 1
80 = 5y + 5
80 - 5 = 5y
75 = 5y
Just reversing both sides we get
5y = 75
Now dividing both sides by 5 we get
y = 15
So the value of y is 15. I hope the procedure for solving the problem is clear to you. In future you can solve such problems with ease following the procedure described.
[tex]80 = 3y + 2y + 4 + 1 \\ \\ 80 = 5y + 4 + 1 \\ \\ 80 = 5y + 5 \\ \\ 80 - 5 = 5y \\ \\ 75 = 5y \\ \\ \frac{75}{5} = y \\ \\ 15 = y \\ \\ y = 15 \\ \\ Answer: \fbox {y = 15} [/tex]