Respuesta :

The correct answer is B.) y > 0

Answer:

Range of a function is defined as those values of y, for which x is Defined.

The given function is

 [tex]y=\sqrt{x+5}[/tex]

Squaring both sides

[tex]y^2=x+5\\\\x=y^2-5[/tex]

x is defined for ,all Real values of y.

For any real y,we get defined value of x.

That is , y ∈ R

→→y∈(-∞,∞)⇒Range