Findtheequationoftheaxisofsymmetryfortheparabola
y =

x^2 - 6x + 1/4

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Tayland7 Tayland7

30-01-2018
Mathematics

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Findtheequationoftheaxisofsymmetryfortheparabola
y =

x^2 - 6x + 1/4

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altavistard altavistard · Answer 1 · 2018-01-30T02:07:29+01:00

The coefficients of this quadratic are {1, -6, 1/4}.

The formula for the x-coordinate of the vertex, which is also the formula for the axis of symmetry, is

-(-6) 6
x = -b/(2a), which here equals x = --------- = ---- = 3 , or x = 3 (answer)
2(1) 2

Findtheequationoftheaxisofsymmetryfortheparabola y = x^2 - 6x + 1/4

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Otras preguntas

Findtheequationoftheaxisofsymmetryfortheparabola
y =

x^2 - 6x + 1/4