x^2 - 6x + 8 = (x - 4)(x - 2)
so the zeroes are 4 and 2 and the line of symmetry is x = 3
Parabola 2 has line of symmetry of x = -4 so a is not true.
and b is true ( no zeroes in common)
When x = 0 Parabola 1 has a y intercept of 8
while Parabola 2 ( (x + 2)(x + 6) has y intercept of 2*6 = 12 so c is not true,
To find minimum va;lues
Parabola 1 vertex form = (x - 3)^2 - 9 + 8 = (x- 3)^2 - 1 So minimum is -1
Parabola 2 has minimum value of -4 so d not true
only b is true
