The probability of no six appearing is: [tex](\frac{5}{6})^{3}=0.5787[/tex] The probability of exactly one six appearing is: [tex]3C1\times\frac{1}{6}\times(\frac{5}{6})^{2}=0.347[/tex] The events 'no six' and 'one six' are mutually exclusive, therefore the probability of no more than one six is given by: 0.5787 + 0.347 = 0.9257
