ayeerubii
ayeerubii
30-10-2017
Mathematics
contestada
The sum of 5 consecutive integers is 265
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tynollette
tynollette
30-10-2017
suppose the first one is n, the second is then n+1, the third is n+2, ....
n+(n+1)+(n+2)+(n+3)+(n+4)=265
5n+10=265
5n=255
n=51
so the 5 consecutive integers are: 51,52,53,54,55
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