Respuesta :

Plasmataco
so -35p^4/36q^3 * 6q^7/49p^9.
The 7p^4s cancel out so you get -5/36q^3 * 6q^7/7p^5
The 6q^3s also cancel out so you get -5/6 * q^4/7p^5
Multiply them together to get -5q^4/42p^5
Serpentiel
[tex]-\frac{35p^4}{36q^3}\cdot\frac{6q^7}{49p^9}=-\frac{35p^4\cdot \:6q^7}{36q^3\cdot \:49p^9}=-\frac{210p^4q^7}{1764p^9q^3}=\frac{5p^4q^7}{42p^9q^3}=\frac{5q^7}{42p^5q^3}=-\frac{5q^4}{42p^5}[/tex]

Otras preguntas