Three friends were born in consecutive years. The some of their birth years is 5982.find the year in which each person was born

Respuesta :

a+b+c=5982
find the average of the three friends 
5982/3=1994
add and subtract one to find the average 
1994+1=1995
1994-1=1993
add all the years together to check 
1993+1994+1995=5983

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