we know that
in the right triangle MNR
[tex]Sin(N\°)=Cos(R\°)[/tex]
[tex]Sin(56\°)=Cos(34\°)[/tex]
Because
[tex]N+R=90\°[/tex]
[tex]56\°+34\°=90\°[/tex] --------> by complementary angles
so
sin ∠MQP=[tex]Sin(56\°)[/tex]
therefore
the answer is the option
D. Cos R and Sin N
