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For each solution below calculate the millimoles of solute.
a.1.90 l of 0.00657 m nacn
b.871 ml of a solution containing 8.49 ppm caco3

Respuesta :

A
(1.62 L) x (0.00332 mol/L NaCN) = 0.00538 mol = 5.38 mmol NaCN

B
Supposing the solvent to be water, and supposing the density of the solution is near that of pure water:
(675 g) x (5.23 x 10^-6) / (100.0875 g CaCO3/mol) = 3.53 × 10^-5 mol = 0.0353 mmol CaCO3.

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