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How many gallons of a 80% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 70% antifreeze?

Respuesta :

mreijepatmat
Let x be the number of gallons.

(x)(80%) + (60)(30%) = (x+60)((70%)

0.8x + 18 = 0.7x +42

0.8x - 0.7x = 42-18

0.1x = 24

and x = 240 Gal.

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