The combustion of propane (c3h8) produces co2 and h2o: c3h8 (g) + 5o2 (g) → 3co2 (g) + 4h2o (g) the reaction of 2.5 mol of o2 with 4.6 mol of c3h8 will produce ________ mol of h2o.

Respuesta :

The answer is 2 mol of H₂O will be produced.
The balanced equation for the chemical reaction is:

c3h8 (g) + 5o2 (g) → 3co2 (g) + 4h2o (g) 
5 moles of O
₂ produces 4 moles of H₂O, and when there is 2.5 mol of O₂, moles of H₂O will be:
2.5 x 4/5 = 2 mol of H₂O

Answer:

2mol of [tex]\rm O_2[/tex] with 4.6 mol [tex]\rm C_3H_8[/tex] will produce 2mol [tex]\rm H_2O[/tex].

Explanation:

The given information is:

[tex]\rm \mathbf{C_3H_8+5O_2\rightarrow3CO_2+4H_2O}[/tex]

2mol of [tex]\rm O_2[/tex] with 4.6 mol of  [tex]\rm C_3H_8[/tex] will produce.....mol of [tex]\rm H_2O[/tex]

As we can see hear, 5mol of [tex]\rm O_2[/tex] produce 4 mols of [tex]\rm H_2O[/tex]

Hence, According to the given equation above,

Mols of [tex]\rm\mathbf{ H_2O}[/tex] produced will be,

[tex]\rm 5molO_2\times\frac{4molH_2O}{5molO_2}[/tex]

[tex]\rm 2.5\times\frac{4}{5}=2molH_2O[/tex]

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