Answer:
The first steps in the solution to the equation [tex]\log_2 x + \log_2 (x-6) = 4[/tex] is, [tex]\log_2 x(x-6) = 4[/tex]
Step-by-step explanation:
Given the equation: [tex]\log_2 x + \log_2 (x-6) = 4[/tex]
Using logarithmic laws;
[tex]loa_b x + \log_b y = \log_b (xy)[/tex]
then;
[tex]\log_2 x(x-6) = 4[/tex]
Therefore, the first steps in the solution to the equation [tex]\log_2 x + \log_2 (x-6) = 4[/tex] is, [tex]\log_2 x(x-6) = 4[/tex]
