[tex]\bf x=
\begin{cases}
\pm \sqrt{5}\\
-7
\end{cases}\implies
\begin{cases}
x=\sqrt{5}\implies &(x-\sqrt{5})=0\\
x=-\sqrt{5}\implies &(x+\sqrt{5})=0\\
x=-7\implies &(x+7)=0
\end{cases}
\\\\\\
\stackrel{\textit{difference of squares}}{(x-\sqrt{5})(x+\sqrt{5})}(x+7)=\textit{original polynomial}
\\\\\\
(x^2-5)(x+7)=y\implies x^3+7x^2-5x-35=y[/tex]
