Volume of tractor = length x width x height = 301.5 x 96.99 x 105.04 = 3,071,630.624
For baseballs of 9 inches:
[tex]9=2\pi r \\ \\ r= \frac{9}{2\pi}[/tex]
Volume = [tex] \frac{4}{3} \pi r^3= \frac{4}{3} \pi \left( \frac{9}{2\pi} \right)^3=12.31[/tex]
Number of 9 inches baseballs = [tex] \frac{3,071,630.624}{12.31} = 249,513[/tex]
For baseballs of 9.25 inches:
[tex]9.25=2\pi r \\ \\ r= \frac{9.25}{2\pi}[/tex]
Volume = [tex] \frac{4}{3} \pi r^3= \frac{4}{3} \pi \left( \frac{9.25}{2\pi} \right)^3=13.37[/tex]
Number of 9.25 inches baseballs = [tex] \frac{3,071,630.624}{13.36} = 229,824[/tex]
Therefore, the tractor can contain between 229,824 and 249,513 baseballs.
