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the distance between the points (2,-1,-8) and (6,-3,4)
a.15
b.11
c.2sqrt(41)
or
d.4sqrt(6)

Respuesta :

Banabanana
[tex]distance= \sqrt{(6-2)^2+(-3-(-1))^2+(4-(-8))^2} \\ \\ =\sqrt{4^2+ (-2)^2+12^2} \\ \\ = \sqrt{16+4+144}\\\\= \sqrt{164} \\\\=2 \sqrt{41} [/tex]


C.

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