Two buses leave a station at the time and travel in opposite directions. One bus travel 18 mi/h slower then the other l. If the two buses are 670mi apart after 5 hours what is the rate of each bus
Well let's call the fast bus b That means the slow bus will be b-18 We know they travel in 5 hours, so multiply them both by 5 So 5b + 5b - 90 = 670 Simplify it down and collect like terms 10b = 580 Isolate b by dividing both by 10 b = 58 The fast bus travelled at 58mph We know the slow bus travels 18mph slower than the fast one 58 - 18 = 40 The slow bus travels at 40mph
