Answer:
[tex]\frac{1}{3x^{6} y^{3} }[/tex]
Step-by-step explanation:
The inital equation would look like this: [tex]\frac{3x^{2} y^{3} }{9x^{8}y^{6} }[/tex]
Then, we simplify. The 3 and the 9 cancel, leaving a 3 on the denominator. Then, the x's cancel, leaving x^(8-2), which is x^6 on the denominator.
The y's cancel out leaving y^(6-3), which is just y^3 on the denominator.
I hope this helped, and if it did, feel free to rate, give a heart, or mark brainliest! :D
