Presumably, the limit to be evaluated is
[tex]\displaystyle\lim_{x\to1}\frac{2x^2+4}{x^2+4x-4}[/tex]
Since the given function is continuous at [tex]x=1[/tex], the limit of function is equal to the value of the function at [tex]x=1[/tex]:
[tex]\displaystyle\lim_{x\to1}\underbrace{\frac{2x^2+4}{x^2+4x-4}}_{f(x)}=f(1)=\frac{2+4}{1+4-4}=6[/tex]
