The motion of the football that is being kicked follows a projectile path and is parabolic in shape. It has a maximum height of meters and the angle with respect to the ground is degrees. The maximum height is the highest position vertically that the ball could reach. From the equations of an object in a projectile motion, we use the equation (V*sin20)^2 = 2gh in order to solve for velocity, V. We do as follows:
((V) (sin(20)))^2 = 2gh
(V^2) (0.342^2) = 92.12
V = √ (92.12 / 0.342^2)
V = 28.06 m/s
The initial velocity of the kick would be 28.06 m/s.
