Respuesta :

[tex]\bf \begin{array}{rllll} (-5&,&\frac{5\pi }{3})\\ \uparrow &&\uparrow \\ r&&\theta \end{array}\qquad \begin{cases} x=rcos(\theta )\\ y=rsin(\theta )\\ ----------\\ x=(-5)cos\left( \frac{5\pi }{3} \right)\\ \qquad -5\cdot \frac{1}{2}\\ \qquad -\frac{5}{2}\\ y=(-5)sin\left( \frac{5\pi }{3} \right)\\ \qquad -5\cdot -\frac{\sqrt{3}}{2}\\ \qquad \frac{5\sqrt{3}}{2} \end{cases}\implies \left(-\frac{5}{2}\ ,\ \frac{5\sqrt{3}}{2} \right)[/tex]

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