A jet fighter flies from the airbase A 300 km East to the point M. Then 350 km at 30° West of North. It means : at 60° North of West. So the distance from the final point to the line AM is : 350 · cos 60° = 350 · 0.866 = 303.1 km Let`s assume that there is a line N on AM. AN = 125 km and NM = 175 km. And finally jet fighter flies 150 km North to arrive at airbase B. NB = 303.1 + 150 = 453.1 km Then we can use the Pythagorean theorem. d ( AB ) = √(453.1² + 125²) = √(205,299.61 + 15,625) = 470 km Also foe a direction: cos α = 125 / 470 = 0.266 α = cos^(-1) 0.266 = 74.6° 90° - 74.6° = 15.4° Answer: The distance between the airbase A and B is 470 km. Direction is : 15.4° East from the North.
