Respuesta :
n(KF)=m(KF)/M(KF)
n(KF)=vc
m(KF)/M(KF)=vc
m(KF)=M(KF)vc
m(KF)=58.10*1.0*0.10=5.81 g≈ 5.8 g
n(KF)=vc
m(KF)/M(KF)=vc
m(KF)=M(KF)vc
m(KF)=58.10*1.0*0.10=5.81 g≈ 5.8 g
Answer: 5.8 g
Explanation: Molarity : It is defined as the number of moles of solute present in one liter of solution.
[tex]Molarity=\frac{\text{given mass of compound}}{\text{molar mass of compound}\times \text{volume of solution in L}}[/tex]
Given: Molar mass of KF= 58.10 g
Molarity of KF= 0.10
Volume of solution= 1.0 L
[tex]0.10=\frac{\text{given mass of KF}}{58.10}\times 1.0[/tex]
[tex]{\text{given mass of KF}}=5.8g[/tex]
