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The equation of the graphed line in point-slope form is ____
y-0=-3/5(x-3),
3y=-5(x-3),
y-3=-3/5(x-0)

and its equation in slope-intercept form is ____
y=-9/5x+3/5
5y=-3(x-3)
y= -3/5x+9/5

The equation of the graphed line in pointslope form is y035x3 3y5x3 y335x0 and its equation in slopeintercept form is y95x35 5y3x3 y 35x95 class=

Respuesta :

ghanami
hello : 
The equation of the graphed line in point-slope form is  : y-0=-3/5(x-3)
because ; when : x=3  y=0  passes by : (3,0)
when : x = -2  y = 3  passes by : (-2, 3)

and its equation in slope-intercept form is : y= -3/5x+9/5
because :  y-0=-3/5(x-3)     : y = -3/5x +9/5

Answer:

8

Step-by-step explanation:

help

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