Respuesta :
This pair of pucks will rotate at the same rate.
Further Explanation:
Hover Puck:
The Hover Puck coasts effectively on a self-produced pad of air until followed up on by an outside power.
Employments of hover puck:
The Hover Puck coasts effectively on a self-produced pad of air until followed up on by an outside power.
• Use one Hover Puck to show themes from Newton's First Law to impacts to reflection.
• Use at least two pucks to examine the protection laws in two measurements.
• Set up a bowling alley utilizing plastic beverage bottles.
Innovation of hover puck:
The First Rubber Hockey Pucks Were Made From Sliced-Up Lacrosse Balls. At the point when the game moved inside, entire balls were initially utilized, yet arena proprietors before long thought that it was desirable over cut them into thirds and keep the center segment. This fundamental plan was the standard by 1885.
hockey puck was developed:
The hockey puck appeared in 1875. It's hazy who really imagined it. Specialists accept the main hockey puck was likely only an elastic ball cut down the middle. This gave players an article with a level side that would slide over the ice.
Subject: physics
Level: High School
Keywords: Hover Puck, Employments of hover puck, Innovation of hover puck, hockey puck was developed.
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The pucks will rotate with the same angular rate even after changing the masses of the puck.
Further Explanation:
The two hover pucks collide with each other and stick to one another after the collision. Use the concept of momentum conservation in order to obtain the final rate of rotation of the pucks.
The conservation of momentum means that the momentum of the two bodies remains equal to the momentum of the combined two bodies after they collide if there is no other means of energy loss.
Concept:
Let the two hover pucks have masses [tex]{m_1}[/tex] and [tex]{m_2}[/tex] which are being rotated at the rate of [tex]{v_1}[/tex] and [tex]{v_2}[/tex] respectively.
We can write the expression for the momentum conservation of the pucks as.
[tex]\fbox{\begin\\{m_1}{v_1}+{m_2}{v_2}=\left({{m_1}+{m_2}}\right)v\end{minispace}}[/tex] …… (1)
Here, [tex]{m_1}[/tex] is the mass of first puck, [tex]{m_2}[/tex] is the mass of the second puck, [tex]{v_1}[/tex] is the linear rate of the first puck, [tex]{v_2}[/tex] is the linear rate of the second puck and [tex]v[/tex] is the final rate of the two hover pucks.
The rate of the rotation of the pucks after collision will be,
[tex]v = \dfrac{{{m_1}{v_1} + {m_2}{v_2}}}{{{m_1} + {m_2}}}[/tex]
Now, when the masses of the two pucks is doubled and the other conditions are kept same.
Substitute [tex]2{m_1}[/tex] for [tex]{m_1}[/tex] and [tex]2{m_2}[/tex] for [tex]{m_2}[/tex] in above expression.
[tex]\begin{aligned}v'&=\frac{{2{m_1}{v_1}+2{m_2}{v_2}}}{{2{m_1}+2{m_2}}}\\&=\frac{{{m_1}{v_1}+{m_2}{v_2}}}{{{m_1}+{m_2}}}\\&=v\\\end{gathered}[/tex]
Thus, the above expression shows that the momentum of the hover pucks remains conserved and the hover pucks rotate with the same angular rate.
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Answer Details:
Grade: High School
Subject: Physics
Chapter: Conservation of Momentum.
Keywords:
Hover, pucks, rotate, momentum, conservation, angular rate, rate of rotation, collide, masses, collision, m1v1, M1V1, (m1+m2)v, m2v2, first puck, second puck, same rate.
