Respuesta :

JavierCollante
1) first, we have to convert the grams to moles of AuCl3 using the molar mass of the molecule. 

molar mass of AuCl3= 197 + (35.5 x 3)= 303.5 g/mol

73.4 g (1 mol AuCl3/ 303.5 g)= 0.242 moles

2) now. let's convert moles of AuCl3 to moles of chlorine gas (Cl2) using the mole-mole ratio

0.242 mol AuCl3 (3 mol Cl2/ 2 mol AuCl3)= 0.363 mol Cl2

3) finally, we convert moles to grams using the molar mass of Cl2.

molar mass of Cl2 = 35.5 x 2= 71.0 g/mol

0.363 mol Cl2 ( 71.0 g/ 1 mol)= 25.8 grams
mahima6824soni

25.8 grams of chlorine gas can be produced from the decomposition of 73.4.

What is chlorine?

Chlorine is a chemical element whose chemical symbol is Cl and atomic number is 17.

Given,

The reaction

[tex]\bold{2AuCl_3 = 2 Au + 3 Cl_2}[/tex]

Step 1: Converting the grams to moles

The molar mass of [tex]\bold{AuCl_3 }[/tex] is 303.33 g/mol

[tex]73.4 g \; \dfrac{1 mol\; AuCl3}{303.5 g} = 0.242\; moles[/tex]

Step2: Calculating the mole ratios

[tex]0.242\; mol\; AuCl_3 \;\dfrac{3 mol\; Cl_2}{2 mol\; AuCl_3} = 0.363\; mol\; Cl_2[/tex]

Step 3: Converting moles to grams

[tex]\bold{molar\; mass\; of Cl_2 = 35.5 \times 2= 71.0\; g/mol}[/tex]

[tex]0.363\; mol\; Cl_2 ( 71.0 g/ 1 mol) = 25.8 grams[/tex]

Thus, the quantity of chlorine gas is 25.8 grams.

Learn more about chlorine, here:

https://brainly.com/question/1127028

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