Answer:
[tex]cos\theta =-\frac{12}{13}[/tex]
Step-by-step explanation:
[tex]tan\theta =\frac{sin \theta}{cos \theta}[/tex]
If tan θ > 0 and sin θ < 0 then cos θ <0
We have sin²θ + cos²θ = 1
That is
[tex]\left ( \frac{-5}{13} \right )^2+cos^2\theta =1\\\\cos^2\theta =1-\frac{25}{169}=\frac{144}{169}\\\\cos\theta =-\frac{12}{13}[/tex]
