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Which of the following describes the graph of y=x^2−144?

The graph has zeroes at x = -12 and x = -12 and it opens downward.

The graph has zeroes at x = 12 and x = -12 and it opens downward.

The graph has zeroes at x = 12 and x = 12 and it opens upward.

The graph has zeroes at x = 12 and x = -12 and it opens upward.

Respuesta :

irspow
y=x^2-144  has zeros when

x^2-144=0

x^2=144

x=√144

x=±12

dy/dx=2x, and d2y/dx2=2  since acceleration is a constant positive when dy/dx=0, y(x) is at an absolute minimum.  So the parabola opens upwards.

So the graph has zeros at -12 and +12 and opens upwards.

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