EmmaB11
EmmaB11
29-04-2017
Mathematics
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mreijepatmat
mreijepatmat
29-04-2017
∫tan²4x.dx=4∫tan²xdx
but tan²x =sec²x-1
===>4∫(sec²x-1)dx = 4[∫sec²dx-∫dx]
===>4∫sec²xdx-4∫dx=====> 4tanx-4x +c
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