An ambulance travels down a high way at a speed of 75.0 mi/h, its siren emitting sound at a frequency of 400 Hz. What frequency is heard by a passenger in a car travelling at 55.0 mi/h in the opposite direction as the car (a) approaches? (b) Moves away from the ambulance?

For speed of sound of c=340m/s:
f'=f((c+Vr)/(c+Vs)) where Vr is speed of receiver (+ if moving towards source) and Vs is speed of source (+ if moving away from receiver)
So A) 596Hz
B) 275Hz

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sp10925 sp10925 · Answer 2 · 2022-05-28T07:39:45+02:00

The frequency is heard by a passenger in a car travelling at 55.0 mi/h in the opposite direction as the car

(a) approaches is 475.85 Hz

(b) Moves away from the ambulance is 337.766 Hz

What is frequency?

The frequency is the number of cycles per second in a sinusoidal wave.

Speed from mi/h to m/s

75 mi/h =33.528 m/s

55 mi/h = 24.5872 m/s

For speed of sound c=340m/s:

f'=f x [(c+Vo)/(c+Vs)]

where Vo =24.5872 m/s is speed of receiver and Vs =33.528 m/s is speed of source

Given is the frequency f =400Hz

a) When car approaches the ambulance, frequency heard is

f'=f x [(c+Vo)/(c-Vs)]

Substitute the value, we get

f' =475.85 Hz

b) When car moves away the ambulance, frequency heard is

f'=f x [(c-Vo)/(c+Vs)]

Substitute the value, we get

f' =337.766 Hz

Thus, the frequency is heard by a passenger in a car travelling at 55.0 mi/h in the opposite direction as the car

(a) approaches is 475.85 Hz

(b) Moves away from the ambulance is 337.766 Hz

Learn more about frequency.

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