Respuesta :
The first one is true. Plugging in 1000 units for x gives c(x) = 200000, which is the minimum the company can sell it for while still making a profit.
It can't be the maximum as the company will want to make a profit.
The third and fourth have mathematical errors. Both will equal 0 and not 800000.
It can't be the maximum as the company will want to make a profit.
The third and fourth have mathematical errors. Both will equal 0 and not 800000.
c(1000)=400(1000)-.2[tex] (1000)^{2} [/tex]
c(1000)=400,000-200,000=200,000
c(2000)=400(2000)-.2[tex] (2000)^{2} [/tex]
c(2000)=800,000-800,000=0
So, 1000 units is going to cost $200,000. I'm not sure how that works with minimum and maximum since it is an exact answer.
Hope that helps though.
c(1000)=400,000-200,000=200,000
c(2000)=400(2000)-.2[tex] (2000)^{2} [/tex]
c(2000)=800,000-800,000=0
So, 1000 units is going to cost $200,000. I'm not sure how that works with minimum and maximum since it is an exact answer.
Hope that helps though.