Respuesta :
Before the first straw is drawn, there are three short straws and [tex]3+4+6=13[/tex] straws in all. Thus, the probability of drawing a short straw first is [tex]\frac{3}{13}[/tex].
After a short straw is drawn, there are two short straws and twelve total straws, a probability of [tex]\frac{2}{12} = \frac{1}{6}[/tex].
Thus, the probability of both of these events occurring is [tex]\frac{3}{13} \cdot \frac{1}{6} = \boxed{\frac{1}{26}}[/tex].
After a short straw is drawn, there are two short straws and twelve total straws, a probability of [tex]\frac{2}{12} = \frac{1}{6}[/tex].
Thus, the probability of both of these events occurring is [tex]\frac{3}{13} \cdot \frac{1}{6} = \boxed{\frac{1}{26}}[/tex].
Answer: 1 /26
Step-by-step explanation: To calculate probability of two dependent events you multiply their probabilities together. Remember that without replacement means you have to subtract one from the denominator. Therefore you should multiply 3/ 13 ⋅ 2/ 12 to get the solution 1/ 26 .
