Respuesta :

apologiabiology
vertex is now at (-1,5)

for
y=a(x-h)^2+k
vertex is (h,k)
so veertex is (-1,5)

y=a(x-(-1))^2+5
y=a(x+1)^2+5
a is a constant, we will asssume that it is 1 because all the choices have 1

y=1(x+1)^2+5
y=(x+1)^2+5

2nd option

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