Iron is obtained commercially by the reaction of hematite (Fe2O3) with carbon monoxide. How many grams of iron are produced if 13.0 moles of hematite react with 38.0 moles of carbon monoxide?

Respuesta :

 CO is the limiting reactant 
( 25.0 x 3 = 75 moles of CO are required) 

Moles Fe = 30.0 x 2 / 3 = 20.0 
mass Fe = 20.0 x 55.847 g/mol=1117 g 


I'm just saying

When 13 moles of hematite react with 38 moles of carbon monoxide, 1,412.7 grams of iron is produced.

How we calculate mass from moles?

Mass of any substance can be calculated by using its moles as:
n = W/M, where

W = required mass

M = molar mass

Given chemical reaction :
Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(s)

From the stoichiometry of the solution, it is clear that:

1 mole of Fe₂O₃ = react with 3 moles of CO

13 moles of Fe₂O₃ = react with 13×3=39 moles of CO

Given moles of CO = 38 moles which is 1 mole less than the calculated moles.

So, CO is the limiting reagent, it means it totally coverts into product.

3 moles of CO = produce 2 moles of Fe

38 moles of CO = produce 2/3×38= 25.3 moles of Fe

Now we convert this moles of Fe into grams by using the above equation, where molar mass of Fe is 55.84 g/mol.

W = n×M, where

W = 25.3 × 55.84 = 1,412.7 grams

Hence, 1,412.7 grams is the mass of iron.

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