Respuesta :
48000=55210(1-0.0109)^t
Solve for t
t=12.77 =13 years
2010+13=2023
So the answer is c
Solve for t
t=12.77 =13 years
2010+13=2023
So the answer is c
Answer:
The city population will first be below 48,000 in the year:
2022
Step-by-step explanation:
It is given that:
In 2010, a city population was 55,210
in 2011 the city population will be
(100-1.09)×55210/100=98.91×55210/100
= 0.9891×55210
in 2012 the city population will be
0.9891×0.9891×55210
we have to find number of years t such that
[tex](0.9891)^{t}55210<48000\\\\(0.9891)^{t}<\dfrac{48000}{55210}\\\\(0.9891)^{t}<0.8694\\\\t=13[/tex]
i.e. the thirteen years from 2010 we will have city population less than 48000
i.e. in the year 2022