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Questions 1. What conclusions can you draw about the results of your first cross, between a homozygous red bull (RR) and a heterozygous red cow (Rr)? Answer:


2. What conclusions can you draw about the results of your second cross, between a heterozygous red bull (Rr) and a heterozygous red cow (Rr)? Answer:


3. What conclusions can you draw about the results of your third cross, between a homozygous white bull (rr) and a homozygous white cow (rr)?

Respuesta :

dexteright02
a)

[tex]RR\:x\:Rr[/tex]
[tex]\underbrace{RR\:x\:Rr}[/tex]
[tex]RR, Rr, RR, Rr[/tex]
[tex]\underbrace{RR,RR}_{50\%},\underbrace{Rr,Rr}_{50\%}[/tex]

Therefore:
Crossing results in 50% (dominant homozygote) and 50% (dominant heterozygote).

b)

[tex]Rr\:x\:Rr[/tex]
[tex]\underbrace{Rr\:x\:Rr}[/tex]
[tex]RR, Rr, Rr, rr[/tex]
[tex]\underbrace{RR}_{25\%},\underbrace{Rr,Rr}_{50\%}, \underbrace{rr}_{25\%}[/tex]

Therefore:
Crossing results in 25% (dominant homozygote), 50% (dominant heterozygote) and 25% (homozygous recessive).

c)

[tex]rr\:x\:rr[/tex]
[tex]\underbrace{rr\:x\:rr}[/tex]
[tex]rr, rr, rr, rr[/tex]
[tex]\underbrace{rr,rr,rr,rr}_{100\%}[/tex]

Therefore:
Crossing results in 100% (homozygous recessive).



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