A jar contains n nickels and d dimes there are 20 coins in the jar, and the total value of the coin s is one dollar and forty cents. how many nickels and how many dimes are in the jar?
A) n + d = 20 B) .05n + .10d = 1.40 Multiplying A) by -.10 A) -.1n -.1d = -2 Then adding it to B B) .05n + .10d = 1.40 -.05n = -.60 n = 12 nickels d = 8 dimes
